R = R 1 + R n t c {\displaystyle R=R_{1}+R_{ntc}}
{ I = U R = 5 V R 1 + R n t c I R 1 = U R 1 R 1 = V m e a s u r e d R 1 {\displaystyle {\begin{cases}I&={\frac {U}{R}}={\frac {5V}{R_{1}+R_{ntc}}}\\I_{R_{1}}&={\frac {U_{R_{1}}}{R_{1}}}={\frac {V_{measured}}{R_{1}}}\end{cases}}} Because I = I R 1 {\displaystyle I=I_{R_{1}}} , we get V m e a s u r e d = R 1 R 1 + R n t c 5 V {\displaystyle V_{measured}={\frac {R_{1}}{R_{1}+R_{ntc}}}5V} or R n t c = R 1 V m e a s u r e d 5 V − R 1 {\displaystyle R_{ntc}={\frac {R_{1}}{V_{measured}}}5V-R_{1}} and R n t c {\displaystyle R_{ntc}} gives the temperature. Of course, it needs to be scaled. But that is not a problem.
β = ln T 1 T 2 T 1 − 1 − T 2 1 {\displaystyle \beta ={\frac {\ln {\frac {T_{1}}{T_{2}}}}{T_{1}^{-1}-T_{2}^{1}}}}
Use two fixed point calibration.